For a dog that weighs w pounds and x inches long to qualify for a certain competition, the difference between w and 3/2 x can no more than 5. If a dog with length 24 inches qualify for the competition, what is one possible weight, in pounds, of this dog?

\lvert w-\dfrac{3}{2}(24)\rvert <5

\lvert w-36\rvert <5



Leave a Reply