Test 7 Section 3 #20 please

This is a funny question because unlike most #20s, there’s not much going on conceptually. However, it’s still an easy one to miss. The best advice I can give about questions like this is to write out every step.

    \begin{align*}&(7532+100y^2)+10(10y^2-110)\\=&7532+100y^2+(100y^2-1100)\\=&100y^2+100y^2+7532-1100\\=&200y^2+6432\end{align*}

So in ay^2+b, we now know that a = 200 and b = 6432. Therefore, a+b=200+6432=6632.