Hi Mike
For question 13 test 1 no calculator, I used plugging in. I made x = 4 and solved to get 42/13. then I plugged 4 into my answer choices and B gave me 42/13.
I am curious as to why you did not use plug in for your answer and explanation.
It might be a stupid question, but on exercise 6 about plugging in, I plugged in 3 for x, and none of the answer choices were correct. Letter c was the closest, but still, 3 raised to 6 equals 729; minus 9 equals 720. okay, but the result for letter c, if y=9, is 72.
So, I wanted to ask you if, on this specific exercise, the only option to get the right aswer is plugging in 2 for x.
(sorry if I said any terms in the wrong way, engish is not my first language)
For the question 8 about plugging in
I plugged in 30 for the number of desks, and so e=25 and c=48. But, it didn’t match any of the answer choices. I don’t understand what went wrong. I checked it over and over again. Pleease help aaaaa
Could you please explain Test 2 Calculator Active #25
Hi Mike, Can you work the solution for Test 7, Section 3, #13? Thanks!
Could you solve Test 6, Section 4, number 18 for me? Thanks!
Practice test 2, section 3 Q10, the answer is C (which you can easily obtain by plugging in x = 0) but is there another way to do or it some other logic you can use?
Thank you!
What’s the best and fastest way to do practise test 3, section 3, question 15? How would you interpret the equation? (which I find very confusing and difficult)
Thank you
How would you do question 11 from practise test 3, the no calculator section? (using the plugging in method?)
Thank you!
For the official practise test 2, section 3, question 4 is listed as a “plugging in” question.
So when I tried it out, I substituted 1 for both variables a and b. That easily allows me to pick option A.
However, one of your rules was to never plug in the values 0 and 1, yet 1 was a viable option for this question.
So how can I know when plugging in 1 will be okay and when it’s a bad idea? Also, is my method correct for this question or would you suggest another way? Thanks so much!
Hi Mike, I find these Qs confusing and I lose valuable time trying to think my way through them (usually get them wrong anyway!) What’s a good stepwise approach? Thanks!
If 6 < |x-3| < 7 and x < 0, what is one possible value of |x| ?
Can you do Test 6 Section 3 #15?
I’m not sure you are answering questions about Practice Test 6 yet. If so, would you please work # 12 in section 3 of that test?
how can you use plug-in for #13 on page 607?
how would you use substitution to figure out #26 on test 4 page 722?