How do you do Test 5 Section 4 #35?

The area of a rectangular garden will be its length times its width: A=lw. If we know that the length of this garden is 5 feet longer than its width, we can substitute l-5 for w: A=l(l-5). From there, we set the area equal to 104 and solve.

    \begin{align*}104&=l(l-5)\\104&=l^2-5l\\0&=l^2-5l-104\end{align*}

At this point, you can factor if that’s how you like to roll, or you can graph. To factor, simply figure out which pair of factors for 104 are 5 apart. 13 and 8 are, so you know that:

    \begin{align*}0&=(l-13)(l+8)\end{align*}

Since we’re dealing with physical lengths, we don’t need to worry about negative solutions. All we need is l=13.

To graph, simply plug the equation into your calculator. You’ll probably need to zoom out once.

ImageJ=1.39u

In the image above, you see that the big parabola formed by y=x^2-5x-104 has a zero at x=13. That’s the value of l you’re looking for.

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