For integers a and b, where 4 is less than or equal to a, which is less than or equal to 6 and 8 is less than or equal to b, which is less than or equal to 10, what is the greatest possible value of 3/(b-a)? Shouldn’t the answer be 3? (since 7-6 is 1 and the greatest value will be 3).. The answer was 1.5.

So 4 ≤ *a* ≤ 6 and 8 ≤ *b* ≤ 10? The greatest possible value of that fraction will be when (*b* *–* *a*) is as small as possible without reaching 0. The smallest *b* is 8, and the biggest *a* is 6. Using those will give you the smallest *b* – *a*, which will be 2. 3/2 = 1.5.