Test 2 Section 4 #33 plz

When a question gives you a point on a graph, you should pretty much always see what happens when you plug that point into the given equation. In this case, that means plugging (3, 6) into f(x)=3x^2-bx+12. That’ll allow us to solve for b. One note here is to remember that the y value of 6 should be plugged in for f(x). That’s because when you see that (3, 6) is on the graph, you know that f(3)=6.

6=3(3)^2-b(3)+12

6=27-3b+12

6=39-3b

-33=-3b

11=b

 

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