Test 1 Section 3 Number 16

Test 1 Section 3 Number 16

One way to go here is to know the difference of two squares: we can factor $t^2-4$ !

$\begin{align*}t^2-4&=0\\(t+2)(t-2)&=0\end{align*}$

That tells you that $t$ must be either 2 or –2.

Since the question told you that $t>0$ , you know the answer must be 2.

You can also get this just by solving more traditionally, and that won’t take much longer.

$\begin{align*}t^2-4&=0\\t^2&=4\\t&=\pm 2\end{align*}$

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