Practice Test 6, number 17, no calc.

I find the way to get questions like this right without worrying too much about fractions is just to break everything down into the most simple steps. In other words, instead of trying to divide by a fraction all at once, first multiply by the denominator to kill the fraction, then solve as you normally would.

    \begin{align*}\dfrac{2}{3}t&=\dfrac{5}{2}\\\dfrac{2}{3}t\times 3&=\dfrac{5}{2}\times 3\end{align*}

That will eliminate the fraction on the left:


Now you just need to divide by 2 (or multiply by \dfrac{1}{2}) to get t all by itself:

    \begin{align*}2t\times \dfrac{1}{2}&=\dfrac{15}{2}\times\dfrac{1}{2}\\t&=\dfrac{15}{4}\end{align*}

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