For #2 on the functions chapter, could you have just added 1 to each side to get f(x) by itself?
f(x-1)= x+1–>f(x)=x+2
I’m having trouble wrapping my head around your previous explanations and wanted to confirm that this method works.

That works in this case because there’s no multiplication going on.

If, for example, you had f(x-1)=3x+1, you could not just add 1 to each side.

In that case, you’d need to think through what’s happening in the function. What happens to x-1 to turn it into 3x+1? Well, first it needs to be multiplied by 3, right?

But when x-1 is multiplied by 3, you get 3x-3.

So after it’s multiplied by 3, you need to add 4 to bring it up to 3x+1.

Your steps in this case were:

  1. Multiply by 3
  2. Add 4

Therefore, f(x)=3x+4.

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