Could you please explain #10 no calculator practice test 9

 

My apologies that this sat in my inbox for a few days! Summer, ya know?

The key to this question is remembering that the corresponding coefficients of equivalent polynomials will be equal. Let’s look at the given equation:

(ax+3)(5x^2-bx+4)=20x^3-9x^2-2x+12

The left side isn’t in expanded form but once it is, we know that the coefficients of the x^3 terms on each side will be equal, and the coefficients of the x^2 terms will be equal, etc. So let’s expand.

(ax+3)(5x^2-bx+4)=20x^3-9x^2-2x+12\\5ax^3-abx^2+4ax+15x^2-3bx+12=20x^3-9x^2-2x+12

Now figure out the coefficients of each power of x

5ax^3+(15x^2-abx^2)+(4ax-3bx)+12=20x^3-9x^2-2x+12\\5ax^3+(15-ab)x^2+(4a-3b)x+12=20x^3-9x^2-2x+12

Here’s where we get to apply the rule I linked to above. We now know that:

5a=20,

15-ab=-9,

4a-3b=-2,

and of course 12=12.

The first equation gives us a=4, use either of the other two to solve for b:

15-4b=-9\\-4b=-24\\b=6

Now that you know a=4 and b=6, you know ab=24.

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