What is the value of x that satisfies the equation \dfrac{1}{x}+\dfrac{4}{2x}=\dfrac{27}{3x^2} ?




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too much time for the monkey to chase the weasel. Right off the bat that 27 looked suspcious its a perfect cube but also fit nicely for x = 3 making the value of one hwne I just for giggles put that 3 for the x on the right side I saw immediately that 1/3 +4/6 ( or 2/3) = 1, so I knew I was home

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