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$\begin{align*}\dfrac{x-8}{x+2}=\dfrac{x-5}{x-1}\end{align*}$
In the equation above, $x\ne -2$ and $x\ne 1$ . What is the value of $x$ that satisfies the equation?

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Comments (2)

GiovanniL53 says:

November 2, 2021 at 10:17 pm

What math chapter covers this in the book?

Mike McClenathan says:

November 3, 2021 at 9:30 pm

algebraic manipulation

How accurate are you?

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