Maybe faster? Since “infinite solutions” means they are the same line, we can just set the 2 equations equal to each other, no? For my solution, I multiplied each term in first equation by 15 to get rid of fractions, multiplied each term in second equation by 7 to rid fractions, then set equations equal. You could then see that -7b must = -60, so set 7b = 60 and solve for b.

## Comments (2)

Maybe faster? Since “infinite solutions” means they are the same line, we can just set the 2 equations equal to each other, no? For my solution, I multiplied each term in first equation by 15 to get rid of fractions, multiplied each term in second equation by 7 to rid fractions, then set equations equal. You could then see that -7b must = -60, so set 7b = 60 and solve for b.

Thats how I did it