\begin{align*}x^3+bx^2+cx+90=0\end{align*}

The equation above has three unique roots at -5, 3, and k. If b, c, and k are constants, what is the value of k ?

A)
B)
C)
D)

 


       
  

Comments (1)

We know the y intercept is at -90

because if x is set to zero we get =-90

x^3 + bx^2+ cx+90 =0
is the same as x^3+Bx^2+cx= -90

we know roots at -5 and 3 so therefore

( X+5) because (-5 +5) gives us the one root of 0 and
(X-3)because (3-3) gives us another zero

so we have ( x+5)(x-3) ( x+k) =-90
setting xs to zero we end up with
5*-3*k =-90
-15(k ) =-90
k= -90/-15
k= 6

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