\begin{align*}(x+11)(x+a)=x^2-b\end{align*}

The equation above is true for all values of x; a and b are constants. What is the value of b ?


 


     

Comments (1)

We dont have time for all that giggley gok you got to get rid of the “oi” – vey of the FOIL. Because you dont have any x values on the right that means the a must= – 11 or else we would have an x component since making it -11 is the only way they can cancel out when the O(utside) and I(nside) get added . When you square 11 you get 121 for the L(ast) component. If you want a kosher meal — one like X^2 -b that L(ast) supper has got to be perfect! I would like to thank both testaments for helping me solve this.

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