In the -plane, the two circles with the equations above intersect at points and . What is the equation of the line that contains both point and point ?A)B)C)D) Loading... Page navigation ← Daily PWN 192 Daily PWN 194 →
Solving it in a different way: Beginning from Step – (x+3)^2 – 25 = (x-3)^2 – 16 (x+3)^2 – (x-3)^2 = 25 – 16 = 9 Using, a^2 – b^2 = (a – b)*(a+b), in the Left Hand Side of the equation, where a = (x+3) and b = (x-3), we get, (x+3)^2 – (x-3)^2 = [(x+3) – (x-3)]*[(x+3) + (x-3)] = [(x+3-x+3)*(x+3+x-3)] = [(6)*(2x)] = 12x Therefore, 12x = 9 x = 0.75 Log in to Reply
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Solving it in a different way:
Beginning from Step –
(x+3)^2 – 25 = (x-3)^2 – 16
(x+3)^2 – (x-3)^2 = 25 – 16 = 9
Using, a^2 – b^2 = (a – b)*(a+b), in the Left Hand Side of the equation, where a = (x+3) and b = (x-3), we get,
(x+3)^2 – (x-3)^2 = [(x+3) – (x-3)]*[(x+3) + (x-3)] = [(x+3-x+3)*(x+3+x-3)] = [(6)*(2x)] = 12x
Therefore, 12x = 9
x = 0.75