In the -plane, the two circles with the equations above intersect at points and . What is the equation of the line that contains both point and point ?A)B)C)D) Loading... Page navigation ← Daily PWN 192 Daily PWN 200 →

Solving it in a different way: Beginning from Step – (x+3)^2 – 25 = (x-3)^2 – 16 (x+3)^2 – (x-3)^2 = 25 – 16 = 9 Using, a^2 – b^2 = (a – b)*(a+b), in the Left Hand Side of the equation, where a = (x+3) and b = (x-3), we get, (x+3)^2 – (x-3)^2 = [(x+3) – (x-3)]*[(x+3) + (x-3)] = [(x+3-x+3)*(x+3+x-3)] = [(6)*(2x)] = 12x Therefore, 12x = 9 x = 0.75 Log in to Reply

## Comments (1)

Solving it in a different way:

Beginning from Step –

(x+3)^2 – 25 = (x-3)^2 – 16

(x+3)^2 – (x-3)^2 = 25 – 16 = 9

Using, a^2 – b^2 = (a – b)*(a+b), in the Left Hand Side of the equation, where a = (x+3) and b = (x-3), we get,

(x+3)^2 – (x-3)^2 = [(x+3) – (x-3)]*[(x+3) + (x-3)] = [(x+3-x+3)*(x+3+x-3)] = [(6)*(2x)] = 12x

Therefore, 12x = 9

x = 0.75