a=x^2
b=(x+1)(x-1)
c=(x+1)^2If x is less than or equal to 0 in the three equations above, what is the ordering of A, B and C
a) A<B<C
b) B<A<C
c) B<C<A
d) C<A<B
e) C<B<A
This is either a bad question or you transcribed it wrong, because if x = 0 or x = –1, you get different answers than if x = –2 or less. So let’s assume this question actually says x is less than –1, and then let’s PLUG INNNNN!!!!!!!!!!!
Say x = –2.
There: c < b < a
You can also graph to solve this one, and graphing will show you precisely why the question as you submitted it doesn’t work. See how the top-to-bottom order of the graphs changes when –1 ≤ x ≤ 0?
Comments (2)
Wouldn’t this statement be false even if a single number acts as an anomaly ie When the question specifies that “x is less than or equal to 0”, how can we ignore the case when putting 0 in the statement gives the order as b less than c less than a
You’re right. The original question probably should say just x < –1 . That's what I'm saying above.