a=x^2

b=(x+1)(x-1)

c=(x+1)^2If x is less than or equal to 0 in the three equations above, what is the ordering of A, B and C

a) A<B<C

b) B<A<C

c) B<C<A

d) C<A<B

e) C<B<A

This is either a bad question or you transcribed it wrong, because if *x* = 0 or *x = *–1, you get different answers than if *x* = –2 or less. So let’s assume this question actually says *x* is less than –1, and then let’s PLUG INNNNN!!!!!!!!!!!

Say *x* = –2.

There: *c* < *b* < *a*

You can also graph to solve this one, and graphing will show you precisely why the question as you submitted it doesn’t work. See how the top-to-bottom order of the graphs changes when –1 ≤ *x* ≤ 0?

## Comments (2)

Wouldn’t this statement be false even if a single number acts as an anomaly ie When the question specifies that “x is less than or equal to 0”, how can we ignore the case when putting 0 in the statement gives the order as b less than c less than a

You’re right. The original question probably should say just x < –1 . That's what I'm saying above.