The digits of a 2-digit integer are K and V. If 10*K+V=16, which of the following equals 61?

A) 10*V+K

B) 10/V +K

C) 10/K +V

D) (K*V)/ 10

E)10/ (K*V)

If K and V are digits, so we know that if 10K + V = 16, then K must be 1 and V must be 6.

Therefore, if we want 61, we can use the same form we’re given and just flip the order. We want the 6 to be the tens term, so multiply V by 10, and we want the 1 to be the ones term, so leave K alone.

10V + K = 10(6) + 1 = 61