Test 2 Section 4 #28

There are a few ways to go here, but I think the easiest is just drawing the line and then using when you know about slope-intercept form to see which choice is the best fit. Just one thing: they’re trying to get you here with the sneaky axis labeling, so be careful. The coordinates of B and D are (–1, 6) and (3, –6), respectively.

t2s4-28

There are those points graphed without all the rest of the diagram’s noise. There are three important things you can see without doing any calculating:

  • The slope is negative.
  • The slope is fairly steep (the line moves down faster than it moves right).
  • The y-intercept is positive.

All the answer choices have negative slopes, so the first thing isn’t all that helpful. The steepness eliminates choices C and D, though, and the positive y-intercept means the answer can’t be A, so it must be B, the only choice that doesn’t start off in slope-intercept form. Put B in that form to confirm:

y = –3(x – 1)
y = –3x + 3

Yep, that works! 🙂

(If it makes you feel better, you can calculate the slope from the endpoints.) \text{slope}=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{-6-6}{3-(-1)}=\dfrac{-12}{4}=-3

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