## Could you please explain #20,practice test 9,calculator?

Could you please explain #20,practice test 9,calculator?

## Hey, Could you please explain #21(practice test #7)

Hey, Could you please explain #21(practice test #7)

## Hi, I have a question for # 4 on pg. 78. Wouldn’t the answer to that question be -3?

Hi, I have a question for # 4 on pg. 78. Wouldn’t the answer to that question be -3?

## QAS March 2021, Section 3, # 20.

Hi Mike… QAS March 2021, Section 3, # 20. Since “no solution,” can you consider each side a separate parallel line & use corresponding coefficients to confirm that k must equal 1/2? Or, what’s the best way to solve?

1/2x + 5 = kx + 7

In the given equation, k is a constant. The equation has no solution. What is the value of k?

## Test 9 Section 4 Question 15

Test 9 Section 4 Question 15

## In the given system of equations, a is a constant. If the system has no solutions, what is the value of a ?

Hi Mike… can you solve this and explain please? Thanks!

ax + 5y = 8
12x + 15y = 10

In the given system of equations, a is a constant. If the system has no solutions, what is the value of a ?

## Hi! May you please explain number 8 from the practice questions in the “lines” chapter?

Hi! May you please explain number 8 from the practice questions in the “lines” chapter? I understand that A is the correct answer after looking at the table values, but I don’t understand it from the equation itself. Thanks!

## How do you do Test 9 section 3 number 20?

How do you do Test 9 section 3 number 20?

## 2x-5y=8 4x+ky=17 For which of the following values of k will the system of equations above have no solution (A)-10 (B)-5 (C)0 (D)5 (E)10

When a system of linear equations has no solution, that means you have parallel lines, which means the lines have the same slope. So put both equations into slope-intercept form (y = mx + b) first: In order for those lines to be parallel, their slopes must be equal, which means 2/5 = -4/k. That means k must be (more…)

## In the xy-plane what is the slope of the line that passes through the origin and makes a 42° angle with the positive x-axis? A. 0.67 B. 0.74 C. 0.90 D. 1.11

Trigonometry does the trick here. Below is that line making a 42° angle with the positive x-axis. I’ve also drawn a dotted segment to make myself a neat little right triangle. Remember that slope is rise over run—how high the line climbs divided by how far it travels right. In this case, the dotted segment (more…)

## In the system of equations above, a and b represent the cost, in dollars, of buying x buffalo wings at two different restaurants…

In the system of equations above, a and b represent the cost, in dollars, of buying x buffalo wings at two different restaurants. What amount of money will get you the same number of buffalo wings at both restaurants?

## Test 5 Section 4 #11

Can you work out problem #11 of section four in Official SAT #5?

## The figure above shows the graph of the function f(x)=ax +b, where a and b are constants. What is the slope of the graph of the function g(x)=-2f(x)

Note that f(x) is a line in slope-intercept form, where a is the slope and b is the intercept. Once you recognize that, you just need to know that, notationally, the –2 in front of f(x) means you multiply the whole thing by –2. So: That’s still a line, but now the slope is –2a. from Tumblr (more…)

## The figure above shows the graph of the function f(x)=ax +b, where a and b are constants. What is the slope of the graph of the function g(x)=-2f(x)

Note that f(x) is a line in slope-intercept form, where a is the slope and b is the intercept. Once you recognize that, you just need to know that, notationally, the –2 in front of f(x) means you multiply the whole thing by –2. So: That’s still a line, but now the slope is –2a. from Tumblr (more…)

## Test 5 Section 3 #13

Hi. Would it be possible for you to explain #13 on SAT practice test 5 on calculator inactive (the tea bag problem)? I think the main reason I found it confusing was the wording, and the SAT explanation for the answer was also a little bit wordy.
Thanks