Test 6 calculator section #34 please!

I’ll give you two good ways to go on this one. First, the algebra. If you know the graph of y=3x^2-14x goes through the point (a,a), then you can substitute a in for x and y and solve!

    \begin{align*}a&=3a^2-14a\\0&=3a^2-15a\\0&=a^2-5a\\0&=a(a-5)\end{align*}

From that, you know a must equal 5, since the question distinguishes between (0,0) and (a,a).

The other way to go is to use your graphing calculator—just find the intersections between y=3x^2-14x and y=x.

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