Test 3 Section 4 #30

This one is yucky. Let’s attack it by substituting. First, we’re told that b=c-\frac{1}{2}, so let’s reflect that (I’m going to use the decimal version of \frac{1}{2} for simplicity):


Now, let’s solve both equations for c:


Because we now have two different equations with c isolated, we can substitute again here to get an equation that only contains xs and ys.


That translates to “x is y minus \frac{1}{4},” so the answer is A.


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