In the equation below, a is a positive integer constant.

    \begin{align*}y=-(x-a)^2+9\end{align*}

When the equation above is graphed in the xy-plane, one of the graph's x-intercepts is at x=8. What is the least possible value of a ?


 


 

Comments (2)

Looking at it right away you can see that what is in the parenthesis must be equal to +/-3 so that x intercept is when y =0
-(+/-3^2) =-9
-9+9 =0

8-5 = 3
8-11=-3
5<8 5 the answer

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