can you please explain number 5 and 7 on Absolute Value

# Mike,I do not understand number 6 in the absolute value section of your book. Why can’t |0| + |7| = 7? Zero is even and 7 is odd.

Mike,

I do not understand number 6 in the absolute value section of your book. Why can’t |0| + |7| = 7? Zero is even and 7 is odd.

# Mike, in your book you wrote |a| = -a ? I thought the absolute value could only be a positive number.

Mike, in your book you wrote |a| = -a ? I thought the absolute value could only be a positive number.

# Test 6 calc section number 28

Test 6 calc section number 28

# Hi Mike, I find these Qs confusing and I lose valuable time trying to think my way through them…

Hi Mike, I find these Qs confusing and I lose valuable time trying to think my way through them (usually get them wrong anyway!) What’s a good stepwise approach? Thanks!

If 6 < |x-3| < 7 and x < 0, what is one possible value of |x| ?

# The area bound by the relationship |x|+|y|=2 is

Subject Test Question:

The area bound by the relationship |x|+|y|=2 is

A) 8

B)1

C) 2

D) 4

E) there is no finite area.

How do you find this algebraically?

# |2x-1| = 4x+5 has how many numbers in its solution set?

Subject Test question:

|2x-1| = 4x+5 has how many numbers in its solution set?

A) 0

B) 1

C) 2

D) an infinite number

E) none of above

How do you find the answer algebraically without graphing it?

# How to solve q19, pg 154, from your study guide. Thanks.

How to solve q19, pg 154, from your study guide. Thanks.

# For a dog that weighs w pounds and x inches long to qualify for a certain competition, the difference between w and 3/2 x can no more than 5…

For a dog that weighs w pounds and x inches long to qualify for a certain competition, the difference between w and 3/2 x can no more than 5. If a dog with length 24 inches qualify for the competition, what is one possible weight, in pounds, of this dog?

# My question regarding making absolute value fall in a particular range…

My question regarding making absolute value fall in a particular range. In your book you gave two example (pg 149) and my question is what value should I consider as the end? is it the highest value or the (highest value+1) . Because in question#19 pg149 you consideed 181 to be the end, when 181 isn’t included! & what if the inequality symbol is less than or equal to, what should I do in that case?

# In the xy plane above, f and g are functions defined by f(x)=abs[x] and g(x)=-abs[x] + 3 for all values x. What is the area of the shaded region bounded by the graphs of the two functions?

Hi mike! This question is from the May 2015 SAT.

(will post photo)

In the xy plane above, f and g are functions defined by f(x)=abs[x] and g(x)=-abs[x] + 3 for all values x. What is the area of the shaded region bounded by the graphs of the two functions?

# For all numbers x and y, let x # y be defined by x # y= |x^2-y^2| + 2…

I’m just going to make up a symbol for better visualization. The symbol will look like this: #

For all numbers x and y, let x # y be defined by x # y= |x^2-y^2| + 2. What is the smallest possible value of x # y?

This was a 2/5 on the difficulty scale yet I somehow didn’t understand this and still got it wrong. I tried to do some weird algebra that got me nowhere so I moved on. Funny thing this was the only question I got wrong in the section.

A 0

B 1

C 2

D 3

E 4

# Weekend Challenge containing an image from a movie you probably haven’t seen

You know the drill by now. The prize this week will, once again, be beta access to the Math Guide, which is really coming along nicely, if I do say so myself. I kinda can’t believe it’s going to top 300 pages, but at this rate we’re definitely heading in that direction. Anyway, to get (more…)

# Absolute values are rare, PWNable.

Disclaimer: this is really minor stuff as far as how often it appears on the SAT, so if you’re looking for quick tips to really raise your score, I suggest you start elsewhere. This kind of question is pretty rare. I trust you already know the very basics of absolute value: that |5| = 5, (more…)