PSAT #1, Section 3, #13
Hi, Mike! Can you explain the second way we can approach question number 6 from the Parabola chapter? (The two points where the higher y-coordinate is also farther from the line of symmetry.) It would be great if you can provide an example. Thank you.
Parabola D in the xy-plane has equation x – 2y^2 – 8y – 11 = 0. Which equation shows the x-intercept(s) of the parabola as constants or coefficients?
A) x = 2y^2 + 8y + 11
B) x = 2(y + 2)^2 + 3
C) x – 3 = 2(y + 2)^2
D) y = – √(x – 3)/2 – 2
The answer is A) which makes me think this is really just a “do you know the definition of this term” kind of question (similar to official practice test 4.4.28). Can you explain for those weak in this? TIA!
Practice Test 4, Section 3, Number 11 (No Calc)
How do you do Test 5 Section 4 #35?
Test 6 calculator section #34 please!
Can you do Test 4 Section 4 Number 28 please?
Test 4 Section 3 #13
Test 1 Section 4 #30
The new SAT requires you to know a number of special equation forms—to know which one you need to use in a given situation, and to know how to get into that form if it’s not the one you’re given by using algebraic manipulation. Some equation forms (vertex form of a parabola and the standard (more…)
If Paul is using a piece of fencing 80 meters long to build a rectangular enclosure for his dog, what is the greatest possible area that can be enclosed?
A video store rents, on average, 240 videos a day for $2.00 each. The store determined that for every $0.25 that it increases the rental fee, the number of daily rentals will decrease by 10. This relationship can be represented by
y=(240-10n)(2+0.25n)
where y is the daily income in dollars from video rentals and n is the number of $0.25 increases. Based on this relationship, at what rental fee per video will the store have its highest daily income?
A)$2
B)$4
C)$4.25
D)$7.75
E)$8
SAT2 question:)
Subject Test Question:
The standard equation of a parabola with focus (2, -3) and directrix x=6 is
B) x-4 = -8(y+3)^2.
I did not get this answer. Instead I got (y+3)^2 = -8(x-4)
The range of the parabola shown in the graph is y>=-4 . If the equation y= ax^2+bx+c is used to represent the graph , what is the value of a ?
A) 1/3
B) 2/3
C) 3/2
D) 3
How to solve q19, pg 154, from your study guide. Thanks.